Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
Answer:
Step-by-step explanation:
0.0057
first number
5
then the rest
7
equal
5.7
There's <u>three</u> zeros <u>behind</u> the number 5 which mean it will be -3
final answer
another example and it will be clear
0.0000403
first number
4
then the rest
03
equal
4.03
There's <u>five</u> zeros <u>behind</u> the number 4 which mean it will be -5
final answer
Answer:48484;8
Step-by-step explanation:
;7&4;&&4:
Answer:
subject?
Step-by-step explanation:
