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Soloha48 [4]
4 years ago
9

3x-2y=14 2x-3y=11 solve algebraically

Mathematics
1 answer:
VARVARA [1.3K]4 years ago
3 0

Answer: x = 4, y = - 1

Step-by-step explanation:

The given system of simultaneous equations is expressed as

3x - 2y = 14 - - - - - - - - - - - - 1

2x - 3y = 11- - - - - - - - - - - - - 2

The first step is to decide on which variable to eliminate. Let us eliminate x. Then we would multiply both rows by numbers which would make the coefficients of x to be equal in both rows.

Multiplying equation 1 by 2 and equation 2 by 3, it becomes

6x - 4y = 28

6x - 9y = 33

Subtracting, it becomes

5y = - 5

y = - 5/- 5 = - 1

The next step is to substitute y = - 1 into any of the equations to determine x.

Substituting y = - 1 into equation 2, it becomes

2x - 3 × - 1 = 11

2x + 3 = 11

2x = 11 - 3 = 8

x = 8/2

x = 4

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