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Ainat [17]
3 years ago
9

Verify the identity. Show your work. (1 + tan^2u)(1 - sin^2u) = 1

Mathematics
1 answer:
yuradex [85]3 years ago
7 0
\bf \textit{Pythagorean Identities}
\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\ 1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\\
[1+tan^2(u)][1-sin^2(u)]=1
\\\\\\\
[sec^2(u)][cos^2(u)]\implies \cfrac{1}{cos^2(u)}\cdot cos^2(u)\implies \cfrac{cos^2(u)}{cos^2(u)}\implies 1
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0=-20.5x+16.35x-0.1245
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The value of x in the given equation -20.5x+16.35x -0.1245 = 0\\ is 0.03

<u>Step-by-step explanation:</u>

The given equation is that -20.5x+16.35x -0.1245 = 0\\

<u>The steps to be followed to solve the equation are :</u>

Add the like terms together to reduce the equation in a simplified form.

Here, there are two x terms and they must be reduced to a single term.

For this, add the both terms together so that the equation is simplified into one x term and a constant term.

⇒ (-20.5x+16.35x) - 0.1245 = 0

⇒ 4.15x-0.1245 = 0

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⇒ 4.15x = 0.1245

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