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Ainat [17]
3 years ago
9

Verify the identity. Show your work. (1 + tan^2u)(1 - sin^2u) = 1

Mathematics
1 answer:
yuradex [85]3 years ago
7 0
\bf \textit{Pythagorean Identities}
\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\ 1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\\
[1+tan^2(u)][1-sin^2(u)]=1
\\\\\\\
[sec^2(u)][cos^2(u)]\implies \cfrac{1}{cos^2(u)}\cdot cos^2(u)\implies \cfrac{cos^2(u)}{cos^2(u)}\implies 1
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Henry located 2 1/4 and 2.1 on a number line. He wrote the following related story:
Rzqust [24]

Answer:

Jerry ran a farther distance and not Henry.

Step-by-step explanation:

We are given the following information in the question:

Jerry rain 2\frac{1}{2} miles and Henry ran 2.1 miles.

Henry claimed that he ran a farther distance.

This is a wrong claim because when we compare:

2\frac{1}{2} and 2.1

2\displaystyle\frac{1}{2} = \displaystyle\frac{5}{2} = 2 + 0.5 = 2.5\\\\2.5 > 2.1

Hence, Jerry ran a farther distance and not Henry.

Henry may have made some mistake in plotting   2\frac{1}{2} and 2.1 on the number line.

4 0
3 years ago
Please help last question
Helga [31]

Find the total of male students:

4 + 6 + 2 + 2 = 14 total males.

There are 2 male juniors.

The probability of a male being a junior is 2/14 = 1/7 = 0.143 = 14.3 = 14%

6 0
3 years ago
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Solve the system of equations.<br> 3x + y = 3 <br> x + y = 2
qwelly [4]
When solving system equations, we can use substitution method or elimination. Today I'm using substitution method.

First name the 2 equations.
3x + y = 3 (1)
x + y = 2 (2)

Now pick one equation and express one algebra in forms of the other.
From (2),
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Now substitute (3) into (1),
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6 - 3 = 2y
y = 1.5

Now substitute y = 1.5 into (2)
x + 1. 5 = 2
x = 2 - 1.5
x = 0.5

Therefore the answer is x = 0.5 and y = 1.5
5 0
2 years ago
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svet-max [94.6K]

I want to say 5 but I'm not sure

8 0
2 years ago
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Determine the greatest common factor of the following expressions<br> (4x2y2, 3xy4, 2xy2
SashulF [63]
12xy i think lol :) hope that helps a bit 
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3 years ago
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