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babunello [35]
3 years ago
7

Need help with u pls

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0

Answer 1:

V =18

Step-by-step explanation:

V/-6 +2 = -1

(- V  +12= -1 ) / 6

- V  +12=  -6

- V = -6 -12

-V = 18

V =18

Answer 2:

Y = -5

Step-by-step explanation:

12y + 25 =  -35

12y = -35 -25

12y = - 60

Y = -5

Answer 3:

X = 6

Step-by-step explanation:

Product of number X and 9 when 4 is added to it makes 58

(X x 9 ) + 4 = 58

X x 9 = 58 - 4

X  x 9 = 54

X = 6

Hence, the number is 6

kozerog [31]3 years ago
3 0

Which one?????????????????

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Jane and her husband deposited $500 in an account on their wedding day and each subsequent anniversary. The money was deposited
zysi [14]
Total = 500 * ([(1 + .07)^26 -1] / .07) -500
Total = 500 * (<span><span>4.8073529249 </span> / .07) -500
</span>Total = 500 * (<span>68.6764703562) -500
</span>Total = <span> <span> <span> 33,838.24
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Source:
http://www.1728.org/annuity.htm

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3 0
3 years ago
Thomas weighs 168 lb how many kilograms does Thomas weigh
Norma-Jean [14]

Answer:

76.2048 Kilograms

Step-by-step explanation:

You would multiply 168 by 0.4536

168 x 0.4536 = 76.2048

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2 years ago
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Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all
barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all are boys. Assume that the probability of having a girl is 47.00​%. ​

a) Create a probability model for the number of children​ they'll have.

X=1,2,3

​P(X=1)=??

P(X=2)= ??

P(X=30=???

​(Round to four decimal places as​ needed

​b) Find the expected number of children.

E(X)= ???

​c) Find the expected number of boys​ they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

             = 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

                                       = 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

       = 0.148875×3 +0.46375×2+0.2491 ×1

      = 1.6232

5 0
2 years ago
Five less than twice a number
a_sh-v [17]
2x-5 is the answer to the question
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2 years ago
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