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lakkis [162]
3 years ago
13

System of equation by elimination 4x-6y=10 and 3x+6y=4

Mathematics
1 answer:
Whitepunk [10]3 years ago
6 0
Solving:

\left \{ {{4x-6y=10\:(I)} \atop {3x+6y=4\:(II)}} \right.

\left \{ {{4x-\diagup\!\!\!\!\!6y=10} \atop {3x+\diagup\!\!\!\!\!6y=4}} \right.

\left \{ {{4x=10} \atop {3x=4}} \right.
----------------------
7x = 14
x =  \frac{14}{7}
\boxed{\boxed{x = 2}}\end{array}}\qquad\quad\checkmark

<span>Now replace the found value of "x" in equation (II) to find the value of "y"

</span>3x+6y=4\:(II)
3*(2) + 6y = 4
6 + 6y = 4
6y = 4 - 6
6y = - 2
y =  \frac{-2}{6}  \frac{\div2}{\div2} \to \boxed{\boxed{y =  \frac{-1}{3}}} \end{array}}\qquad\quad\checkmark

Answer:
x = 2
y = - 1/3
<span>
</span>
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