Question

System of equation by elimination 4x-6y=10 and 3x+6y=4

Answer 1

Solving:

$\left \{ {{4x-6y=10\:(I)} \atop {3x+6y=4\:(II)}} \right.$

$\left \{ {{4x-\diagup\!\!\!\!\!6y=10} \atop {3x+\diagup\!\!\!\!\!6y=4}} \right.$

$\left \{ {{4x=10} \atop {3x=4}} \right.$
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$7x = 14$
$x = \frac{14}{7}$
$\boxed{\boxed{x = 2}}\end{array}}\qquad\quad\checkmark$

Now replace the found value of "x" in equation (II) to find the value of "y"

$3x+6y=4\:(II)$
$3*(2) + 6y = 4$
$6 + 6y = 4$
$6y = 4 - 6$
$6y = - 2$
$y = \frac{-2}{6} \frac{\div2}{\div2} \to \boxed{\boxed{y = \frac{-1}{3}}} \end{array}}\qquad\quad\checkmark$

Answer:
x = 2
y = - 1/3