Question

What is the perimeter of the figure?

Answer 1

Answer:

The perimeter of the figure is,  $68 \dfrac{1}{2}$ yd

Step-by-step explanation:

The perimeter of the figure is,

$(10\dfrac{1}{3} + 24\dfrac{1}{4} + 15\dfrac{2}{3} + 18\dfrac{1}{4})$ yd

= $((10+24+15+18)+ (\frac {1}{3} + \frac {2}{3} + \frac {1}{4} + \frac {1}{4}))$ yd

=$(67 + 1 + \frac{1}{2})$ yd

=$68 \dfrac{1}{2}$ yd

We know that if there is a polygon with side lengths $a_{i}$ unit ∀

i = 1(1}n where n ∈ N - {1, 2}

then, it's perimeter is given by,

$\sum_{i=1}^{n}a_{i}$  unit