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dusya [7]
3 years ago
10

Which of the following is an extension of the hoof wall and runs along the side of the frog?

Advanced Placement (AP)
1 answer:
Anna007 [38]3 years ago
5 0

Answer:bars

Explanation: its primary purpose is the control the movement of the back of the hoof

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Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the
KIM [24]

Answer:

T_{2020} = 15

Explanation:

Given

T_1 = 10

T_2 = 20

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

<em>This is proved as follows;</em>

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1

<em>Assume n = 3</em>

T_{3} = \frac{T_1 + T_2}{2}

<em>Multiply both sides by 2</em>

2 * T_{3} = \frac{T_1 + T_2}{2} * 2

2T_{3} = T_1 + T_2

<em>Assume n = 4</em>

T_{4} = \frac{T_1 + T_2 + T_3}{3}

T_{4} = \frac{(T_1 + T_2) + T_3}{3}

Substitute 2T_{3} = T_1 + T_2

T_{4} = \frac{2T_3 + T_3}{3}

T_{4} = \frac{3T_3}{3}

T_{4} = T_3

Assume n = 5

T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}

T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}

Substitute 2T_{3} = T_1 + T_2 and T_{4} = T_3

T_{5} = \frac{2T_3 + T_3 +T_3}{4}

T_{5} = \frac{4T_3}{4}

T_{5} = \frac{(5-1)T_3}{5-1}

<em>Replace 5 with n</em>

T_{n} = \frac{(n-1)T_3}{n-1}

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

T_{n} = T_3

Hence,

T_{2020} = T_3

Calculating T_3

T_{3} = \frac{10 + 20}{2}

T_{3} = \frac{30}{2}

T_{3} = 15

Recall that T_{2020} = T_3

T_{2020} = 15

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4 years ago
What would happen if an iron ball ten times more massive than the sun was placed at the edge of our solar system?
klasskru [66]
Nothing...We would all die due to the chill.
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3 years ago
HELPPPPP PLEASEE WILL mark brainliest
Basile [38]

Answer:

Explanation:

The CORRECT answer is C as the birth weight distribution and hence its histogram should be symmetrical from its mean value.

6 0
3 years ago
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A ball is thrown at the ground from the top of a tall building. The speed of the ball in meters per second is v(t)=9.8t+v0, were
EleoNora [17]

Answer:

      V_0=2.7m/s

Explanation:

The speed of the ball in meters per second is

      V(t)=9.8t+V_0

Where t denotes the number of seconds since the ball has been thrown and V_0 is the initial speed of the ball.  Then:

     V(2)=9.8(2)+V_0\\\\V(2)=19.6+V_0

If the ball travels 25 meters during the first 2 seconds after it is thrown, what was the initial speed of the ball

Also, for constant acceleration motion, the average velocity is equal to the sum of final and initial velocities divided by 2 and to the distance divided by the time:

         \dfrac{V(t)+V_0}{2}=\dfrac{d}{t}

Where you know:

  • t = 2s
  • V(2)=9.8(2)+V_0=19.6+V_0
  • d = 25m

Substituting (the units are ommited in the equationn, but added at end of the answer):

     \dfrac{V(2)+V_0}{2}=\dfrac{25}{2}

     V(2)+V_0=25

Thus, you have a system of equations:

     V(2)+V_0=25

     V(2)=19.6+V_0

Substituting the second into the first:

      19.6+V_0+V_0=25\\\\19.6+2V_0=25

      2V_0=25-19.6\\\\V_0=5.4/2\\\\V_0=2.7m/s

5 0
3 years ago
If ABD measures 48 degrees .what is the measure of DBC?
pashok25 [27]
The measure of DBC is 78
Have a great day! :)
6 0
3 years ago
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