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Digiron [165]
3 years ago
10

Alexander has a rectangular shed that has a width of 200cm. the length of it is 3 times the width what is the length?

Mathematics
1 answer:
adoni [48]3 years ago
4 0
Width=200 cm, length=3 times 200(width)=600 cm

lights around the shed would be perimeter.
(200 x 2) + (600 x 2)=400+1200=1600 cm.
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Twenty-five blue and twenty-five yellow marbles are placed in a jar. Thirty-four marbles are removed from the jar and put in a s
GrogVix [38]

Answer:

a) Let b represent the number of blue marbles placed in the second jar. Then 34-b is the number of yellow marbles in the second jar, and 25 - (34-b) is the number of yellow marbles remaining in the first jar. That value simplifies to b-9. The positive difference between b and (b-9) is 9.  

b) Let n, d, p represent the numbers of nickels, dimes, and pennies, respectively.  

.. (5n + 10d + p)/(n + d + p) = 7 ... the average value of the collection is 7 cents per coin  

.. (5(n-1) + 10d + (p+5))/((n-1) + d + (p+5)) = 6 ... replacing one nickel with pennies changes the average to 6 cents per coin  

Multiplying by the denominator and subtracting the right side of each resulting equation gives  

.. 10d + 5n + p = 7d + 7n + 7p  

.. 10d + 5n + p = 6d + 6n + 6p + 24  

Subtracting the second equation from the first gives  

.. 0 = d + n + p - 24 ... tells us the total number of coins is 24. This tells us the total value is $1.68 = 24*$0.07.  

This sum will consist of at least 3 pennies. If that is all the pennies, then the remaining 21 nickels and dimes must add to $1.65. If all were nickels, the value of the 21 coins would be $1.05. We have $0.60 more than that. For each nickel traded for a dime, we gain $.05, so 12 of the 21 nickels must be traded for dimes to raise the total coin value to $1.65.  

Alternatively, you can write two equations in the two unknowns:  

.. d + n = 21  

.. 10d + 5n = 165  

Subtracting 5 times the first equation from the second gives  

.. 5d = 60 ... which gives the same answer as reasoned above.  

There are 3 pennies, 9 nickels, 12 dimes. (If there are 8 pennies to start, then the number of nickels is zero, so it is impossible to trade one for 5 pennies. The solution shown is the only one.)

7 0
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Answer:

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Step-by-step explanation:

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Number of chocolate = 225

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Step-by-step explanation:

7 0
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velikii [3]

Answer:

The answer is "Option A"

Step-by-step explanation:

Using the range difference to calculate the maximum and minimum value.

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R(c) = Max(c) - Min(c) = 13.2

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For point A:

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equate both of them

13.2 + Min(c) = 9.6 + Min(g)Min(g) - Min(c) = 3.6

It indicates that Min(c) surpasses Min(g), whereas Max(g) exceeds Max (c).

Therefore, the Max is picked for g for all penguins and the minimum is picked for c.    

Range of all penguins = Max(g) - Min(c) = x + 5.8 - x + 13.2 = 19

Therefore, it will be determined as the option.

For point B:

In estimating the range the median height cannot help.

For point C:

In order to calculate the variety, the connection between both the mean height cannot be sued.

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Answer:

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Step-by-step explanation:

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