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erica [24]
3 years ago
5

Question 2 (5 points)

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

It's a

Step-by-step explanation:

This is a quadratic expression with the highest power of X being 2.

The coefficient of X² = 1

Note that the general form of a quadratic equation is aX² + bX + C

In this question,

a = 1

b = 7

C = 10

First step is to multiply a and C ( a x C)

= 1 X 10 = 10

Then, find 2 factors of 10 which can both add up to give 7, the coefficient of X given in the question.

The possible factors of 10 are 5 and 2. The sum of 5 and 2 is

5 + 2

Hence, the equation can be written as;

X² + 7X + 10 = X² + 5X + 2X + 10

The next step is to group using a bracket and factorise each bracket individually

(X² + 5X) + (2X + 10) =

X( X + 5) + 2( X + 5) =

(X + 5) (X + 2)

(X + 5) (X + 2) are the factors of the quadratic equation, X² + 7X + 10

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Answer:


Step-by-step explanation:


The area of the rectangle is a product of its length and width.

If g is the area of Shannon's garden, and its length is 18 feet and 27 feet, the equation that represents area g is:

g = 18 feet * 27 feet


If we multiply them, we will find that the area of the garden is:

g = 486 square feet


Read more on Brainly.com - brainly.com/question/3621594#readmore


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2% of the population suffers from the terrible disease conditionitis. The test for conditionitis comes back positive 98% of the
vlabodo [156]

Answer:

8% probability that he or she actually has the disease

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?

This means that:

Event A: Test comes back positive.

Event B: Having the disease.

Test coming back positive:

2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that P(A|B) = 0.98

For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.

Then

P(A) = 0.02*0.98 + 0.98*0.23 = 0.245

Finally:

P(B|A) = \frac{0.02*0.98}{0.245} = 0.08

8% probability that he or she actually has the disease

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