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Tresset [83]
3 years ago
9

Evaluate |5 - 15|. please heeeeeeeelp?

Mathematics
1 answer:
Natali [406]3 years ago
5 0

I think the answer is 10.

Although 5-15=-10

you have those bracket thingies, it's called a modulus right?

they make everything positive in a sense.

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What is the missing coefficient of the x-term of the product (–x – 5)2 after it has been simplified?
valina [46]

we have

(-x-5)^{2}

we know that

(-x-5)^{2}=(-x-5)*(-x-5)

To multiply two binomial I can use the FOIL method

(-x-5)*(-x-5) =(-x)*(-x)+(-x)*(-5)+(-5)*(-x)+(-5)*(-5)\\ =x^{2} +5x+5x+25\\ =x^{2} +10x+25

therefore

the answer is

the missing coefficient of the x-term is 10


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The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
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4 years ago
Leticia charges 8$ per hour to babysit. She babysat Friday night for 4 hours ,and then she babysat again on saturday.She earned
BaLLatris [955]
Leticia babysat on Saturday for 5 hours. She already babysat for 4 hours which makes it (8 x 4) =$32 But she earned $72 so the rest $40 / 8 =5 hours 
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3 years ago
In square $ABCD$, $E$ is the midpoint of $\overline{BC}$, and $F$ is the midpoint of $\overline{CD}$. Let $G$ be the intersectio
tamaranim1 [39]
Draw DH perpendicular to AE.

By the Side-Angle-Side postulate ΔABE  = ΔBEF.

this is the enitre answer: https://web2.0calc.com/questions/in-square-abcd-e-is-the-midpoint-of-line-bc-and-f-is-the-midpoint-o...

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