Answer:
f^-1(x) = (x +5)/3
also = 1/3 x + 5/3
Step-by-step explanation:
Just to be clear, the ^-1 has nothing to do with negative exponents. It just unfortunately looks the same as a negative exponent.
Anyway, there's three basic steps. First write y instead of f(x). Then switch the x and y. Then solve for y.
f(x) = 3x - 5
write y in place of f(x).
y = 3x - 5
SWITCH x and y.
x = 3y - 5
SOLVE for y.
-3y + x = -5
-3y = -x - 5
y = (-x - 5)/-3
y = (x + 5)/3
OR
y = (1/3)x + 5/3
f^-1(x) = 1/3 x + 5/3
We use scientific notation to make it easier to represent numbers very small to very large. EX: 6,000 Scientific Notation: 6^3
Hello from MrBillDoesMath!
Answer:
-5, 0 (multiplicity 2), +4
Discussion:
Let f(x) = x^4 + x ^3 - 20 x^2
Factor x^2 from each term:
f(x) = x^2 ( x^2 + x - 20) = x^2 ( x +5) (x-4)
f = 0 when x = 0 (multiplicity 2) and x = -5 or x = 4
Regards,
MrB