If you want a line perpendicular to that containing (-2,-3):
1. put equation in slope-intercept form
2y=-4x+8
y=-2x+4
2. find the slope of the perpendicular line:
the slope is the opposite reciprocal of the original slope.
so, the original slope is -2
the opposite reciprocal is 1/2
3. find b
the point slope equation is y=mx+b
-add slope
y=(1/2)x+b
- use your point (-2,-3) to plug in known values for x and y
-3=(1/2)(-2)+b
-solve
-3=-1(b)
b=3
your equation is y=(1/2)x+3
