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maks197457 [2]
3 years ago
15

What is the solution for 5p-9=2p+12

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

p = 7

Step-by-step explanation:

Step 1: Subtract 2p from both sides.

5p − 9 − 2p = 2p + 12 − 2p

3p−9=12

Step 2: Add 9 to both sides.

3p − 9 + 9 = 12 + 9

3p = 21

Step 3: Divide both sides by 3.

\frac{3p}{3} = \frac{21}{3\\}

p = 7

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Answer:

p = 0.513

Step-by-step explanation:

There are 212 families with exactly 3 children. So in all, there are 212*3 = 636 children.

Of those,

The number of girls is:

81 + 76*2 + 31*3 = 326

That is, 326 girls out of 636 children.

Then

p = \frac{326}{636} = 0.513

3 0
4 years ago
A grocery store recently sold several cans of soup.
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21/60

Step-by-step explanation:

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Ruby misses 4% of the free throws she attempts in a season. How many total free throws did she attempt if she missed 46?
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Honestly I don’t even know what this is sorry I tried
5 0
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Please answer ASAP!!<br>plssss
34kurt

Answer:

86°

Step-by-step explanation:

b = 29× 2 = 58

d= [180-(86+29)]×2 = 130

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6 0
3 years ago
Calculate x for each of the following right angled triangles.
Sphinxa [80]

\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}

<h3>(a) x = 6.5 cm </h3><h3>(b) x = 10 cm</h3><h3>(c) x = 7 cm</h3><h3>(d) x = 7.9 cm</h3>

Step-by-step explanation:

To find an unknown side of a right angled triangle we use a theorum called pythagorus theorum..

<h3>Formula :</h3>

(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2

(h)^2 = (p)^2 + (b)^2

<h3>therefore, </h3>

(a) hypotenuse = x cm, base = √30 cm, perpendicular = √12 cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (x)^2 = (√12)^2 + (√30)^2

→ x^2 = 12 + 30

→ x^2 = 42

→ x = √42

→ x = 6.480...

→ x = 6.5 cm. (approx)

<h3>___________________________</h3>

(b) hypotenuse = √300 cm, base = √200 cm,perpendicular = x cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (√300)^2 = (x)^2 + (√200)^2

→ 300 = x^2 + 200

→ x^2 = 300 – 200

→ x^2 = 100

→ x = √100

→ x= 10 cm.

<h3>___________________________</h3>

(c) hypotenuse = √66 cm, base = √17 cm,perpendicular = x cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (√66)^2 = (x)^2 + (√17)^2

→ 66 = x^2 + 17

→ x^2 = 66 – 17

→ x^2 = 49

→ x = √49

→ x = 7 cm.

<h3>___________________________</h3>

(d) hypotenuse = x cm, base = 5√12 cm,perpendicular = 2√3 cm.

<h3>by formula,</h3>

→ h^2 = p^2 + b^2

→ (x)^2 = (2√3)^2 + (5√12)^2

→ x^2 = 12 + 50

→ x^2 = 62

→ x = √62

→ x = 7.874...

→ x = 7.9 cm. (approx)

<h3>___________________________</h3>

<h3>Hope it helps you!!</h3>
7 0
2 years ago
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