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Schach [20]
3 years ago
11

Classrooms on one side of the science building are all numbered with consecutive odd integers. If the first​ room, the room with

the smallest classroom​ number, on this side of the building is numbered k​, write an expression in k for the sum of the first five classroom numbers in a row. Then simplify this expression. The sum of the first five classroom numbers in a row is
Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

The sum of the first five classroom numbers in a row is 5k + 20

Step-by-step explanation:

Since the smallest classroom​ number on the side of the building is numbered k​ and each consecutive odd integer is separated by a difference of  

2.

Therefore:  

k is the first class room.

k +  2  is the second class room.

k +  4  is the third class room.

k + 6 is the third class room.

k + 8 is the fifth class room.

The sum of the five consecutive class rooms are given as:

k + (k + 2) + (k + 4) + (k + 6) + (k + 8)

collecting alike terms we get

=  k + k + k + k + k + 2 + 4 + 6 + 8

= 5k + 20

Therefore, The sum of the first five classroom numbers in a row is 5k + 20.

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Answer:

easy peasy,

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all in this case would be,

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hence the 100th term would be,

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4 years ago
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7 0
3 years ago
Use the mapping shown above to show the value of the function f(x) at each point.
julsineya [31]

Answer:

The value of the function f(x) at each point is f(-1) = 5, f(0) = 3, f(1) = 5, f(2) = 11, f(3) = 21 ⇒ A

Step-by-step explanation:

Let us use the mapping shown to solve the question

∵ f(x) = y

∵ x is the domain

∵ y is the range

→ From the figure use x from the domain and y from the range, where

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∵ x = -1 and the corresponding value of y is 5

∴ f(-1) = 5  

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∴ f(2) = 11

∵ x = 3 and the corresponding value of y is 21

∴ f(3) = 21

The value of the function f(x) at each point is f(-1) = 5, f(0) = 3, f(1) = 5, f(2) = 11, f(3) = 21

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3 years ago
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