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3 years ago

BANANANANANANANA HELP W/ problem

Mathematics

2 answers:

sertanlavr [38]3 years ago

6 0

21/9
....................

blondinia [14]3 years ago

6 0

21/9 is the answer because 7x3=21 then over 9

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Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

Verify each solution

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0

3 years ago

Read 2 more answers

Janet can plant nine feet of carrots in 15 minutes while her daughter Amy can plant 17 feet of carrots in half an hour.

Lena [83]

Answer:

Step-by-step explanation:

In order to find who is more efficient at planting carrots, we want to put both ratios in terms of the same amount of time.

For simplicity, lets see how many carrots each can make in 1 hour.

$Janet:\\9ft \: in \: 15 \:minutes$

$\frac{9ft}{15min} = \frac{xft}{60min}\\x = \frac{60*9}{15} = 36$

Janet can plant 36 feet of carrots in one hour

$Amy:\\\frac{17ft}{30min} = \frac{xft}{60min}\\x = \frac{17*60}{30} = 34$

Amy can plant 34 feet of carrots in one hour

So, Janet can plant carrots more quickly

6 0

3 years ago

4.624 to the nearest 10m

lianna [129]

4620 mhope this helps

7 0

3 years ago

Felipe, Pedro y Miguel son fanáticos del cine. Felipe asiste cada 3 días; Pedro cada 6 días y Miguel cada 5 días. Los tres van j

lilavasa [31]

Answer:

Opción C, 30 días.

Step-by-step explanation:

Sabemos que:

Felipe asiste al cine cada 3 días

Miguel asiste cada 5 días.

Pedro asiste cada 6 días.

Los tres van juntos un día, ¿dentro de cuántos días irán otra vez juntos?

Los 3 volverán a ir juntos luego de N días, tal que N es el menor múltiplo común de 3, 5 y 6.

Como 6 es múltiplo de 3, podemos ignorar al 3, y solo considerar al menor múltiplo en común de 5 y 6.

Además, como podemos reescribir estos números como un producto de números primos, así obtenemos:

6 = 2*3

5 = 5*1

Estos números no comparten factores entre ellos, por lo que el menor múltiplo entre 5 y 6 es simplemente 5*6 = 30

Entonces podemos concluir que N = 30

Felipe, Pedro y Miguel irán juntos al cine nuevamente dentro de 30 días.

La opción correcta es C.

5 0

3 years ago

Marcelo can select from 2 types of oranges and 3 types of peaches. If he randomly selects 1 orange and 1 peach, how many possibl

ICE Princess25 [194]

6

2x3=6

oranges-
peaches-

possible combination:
1-

2-

3-

4-

5-

6-

8 0

3 years ago