Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg
so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²
so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x
so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7
you should place it 3√7ft or about 7.9 or 8ft away
Let me think this through again and I will come back to you! 2.22 graph
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Answer:
B
Step-by-step explanation:
x - 5/8 + 1/8 = 6/8 = -3/8 if u simplify
to simplify u need to see how many times it can be shrunk to do it
hope that helped
