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4 years ago

Find the following product if possible. Explain if it is not possible. (See picture)

Mathematics

1 answer:

Nataly_w [17]4 years ago

4 0

Answer:

The answer to your question is the letter a

Step-by-step explanation:

| 1 4 -1 | | 2 -1 |

| 3 2 2 | | 0 3 | Product = 2 x 3 and 3 x 2 = 2 x 2

| 5 2 | It is possible to do this product,

the result will be a 2 x 2 matrix

Process

1.- Multiply first row by first column and second row by second column.

2.- Multiply the second row by the first column and second row by the second column.

= (1 x 2) + (4 x 0) + (-1 x 5) = 2 + 0 - 5 = -3

= (1 x -1) + (4 x 3) + (-1 x 2) = -1 + 12 - 2 = 9

= (3 x 2) + (2 x 0) + (2 x 5) = 6 + 0 + 10 = 16

= (3 x -1) + (2 x 3) + (2 x 2) = -3 + 6 + 4 = 7

Result

| 3 9 |

| 16 7 |

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Once every three years, the Board of Governors of the Federal Reserve System collects data on household assets and liabilities t

kvv77 [185]

Answer:

C. The distribution of the value of transaction accounts is a right-skewed distribution.

Step-by-step explanation:

Some definitions

A skewed right distribution is one in which the tail is on the right side. On simple words we have most of the values on the left part of the distribution.

And present the following property:

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For our case we have that $Mean= 270000$ and $Median=94500$

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C. The distribution of the value of transaction accounts is a right-skewed distribution.

6 0

3 years ago

Read 2 more answers

(9x-9)(9×+9), your finding the difference between two squares. im have some trouble in how to solve it.

stich3 [128]

Answer:

81x² - 81

Step-by-step explanation:

Step 1: Write expression

(9x - 9)(9x + 9)

Step 2: Expand by FOIL

81x² + 81x - 81x - 81

Step 3: Combine like terms

81x² - 81

8 0

4 years ago

Write the standard equation of a circle with center (-2,5) and the point (4,13) on the circle

n200080 [17]

since the point (4,13) is on the circle, then the distance from the center to it, is the radius of the circle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{13})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-2)]^2+[13-5]^2}\implies r=\sqrt{(4+2)^2+(13-5)^2} \\\\\\ r=\sqrt{36+64}\implies r=\sqrt{100}\implies r=10 \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-2}{ h},\stackrel{5}{ k})\qquad \qquad radius=\stackrel{10}{ r}\\[2em] [x-(-2)]^2+[y-5]^2=10^2\implies (x+2)^2+(y-5)^2=100$

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3 years ago

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