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seraphim [82]
3 years ago
13

What is the rise of ramp if slope is 2% and run is 4 feet

Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

.08 feet

Step-by-step explanation:

So slope=rise/run.

You are given slope is 2% or .02.

You are also given run is 4 ft.

Plug these into the formula

.02=rise/4

To solve this for rise multiply both sides by 4:

4(.02)=rise

.08=rise

The rise is .08 feet.

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Roman55 [17]

Answer:

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Step-by-step explanation:

It’s 2 secant lines on a circle.

https://www.mathplanet.com/education/geometry/circles/advanced-information-about-circles

Look at that website. The part says that (ab*ad)=(ac*ae)

Doing that, we get

9*(9+11x)=10(10+8x)

81+99x=100+80x

19x=19

X=1

4 0
3 years ago
Please solve this exponential equation 3^2x-4(3^x+1)+27=0
Mumz [18]

3²x-4(3²x+1)+27=0

9x-4(9x+1)+27=0

9x-4×9x-4×1+27=0

9x -36x -4 +27=0

9x-36x= 4-27

-27x= -23

x= -23/-27

x= 23/27

5 0
2 years ago
Naomi pays $1.50 each time she rides the city bus. She has already ridden the bus 18 times so far this year. The expression 1.50
Mashutka [201]

Answer:

D, 1.50(18)

Step-by-step explanation:

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4 0
3 years ago
A candy store has ten giant pieces of candy! Find the probability of each event. There are 4 gumdrops, 3 lolipops, 2 jellybeans,
AveGali [126]

Answer:

1. P = 9/90 = 1/10

2. P = 16/90 = 8/45

3. P = 10/90 = 1/9

4. P = 4/90 = 2/45

Step-by-step explanation:

Total no. of candy = 10

No. of Gumdrops = 4

No. of Lollipops = 3

No. of Jellybeans = 2

No. of Peppermint = 1

1. To find the probability that the child will pick a peppermint or jellybean, we will add the probabilities of both the candies.

P(Peppermint) = No. of Peppermint/Total no. of candy

                        = 1/10

P(Jellybean) = No. of Jellybean/Total no. of candy

                    = 2/10

P(Peppermint or Jellybean) = 1/10 + 2/10

P(Peppermint or Jellybean) = 3/10

Then, the child picks a lollipop. Note that after picking a peppermint or a jellybean, the number of candies left are 9. So,

P(Lollipop) = No. of Lollipops/Total no. of candy

P(Lollipop) = 3/9

To compute the probability that the child will pick a peppermint or a jellybean and then a lollipop,

P = P(Peppermint or Jellybean) x P(Lollipop)

  = 3/10 x 3/9

P = 9/90 = 1/10

2. Probability that a child will pick a lollipop or peppermint:

P(Lollipop or Peppermint) = P(lollipop) + P(peppermint)

                                          = 3/10 + 1/10

P(Lollipop or Peppermint) = 4/10

Then the child picks a gumdrop. Note that the number of candies remaining are 9. So,

P(Gumdrop) = 4/9

The probability that the child picks a lollipop or peppermint and then a gumdrop:

P = P(Lollipop or Peppermint) x P(Gumdrop)

  = 4/10 x 4/9

P = 16/90 = 8/45

3. Probability that a child will pick a jellybean:

P(Jellybean) = No. of Jellybeans/Total no. of candy

P(Jellybean) = 2/10

Then the child picks a peppermint or a gumdrop. Note that one candy has been picked out so there are 9 candies left in total.

P(Peppermint or Gumdrop) = P(peppermint) + P(Gumdrop)

                                              = 1/9 + 4/9

P(Peppermint or Gumdrop) = 5/9

The probability that a child picks a jellybean then a peppermint or a gumdrop is:

P = P(Jellybean) x P(Peppermint or Gumdrop)

  = 2/10 x 5/9

P = 10/90 = 1/9

4. P(peppermint) = 1/10

Then the child picks a gumdrop. (remaining candies are 9)

P(Gumdrop) = 4/9

Probability that a child will pick a peppermint then a gumdrop:

P = P(peppermint) x P(gumdrop)

  = 1/10 x 4/9

P = 4/90 = 2/45

5 0
3 years ago
In circle O, central angle COD has a measure of 48°. Find the measure of arc BC. In your final answer, include all of your work.
igor_vitrenko [27]
This is the concept of geometry;
to get the length of arc BC we shall proceed as follows;
angle DOC=48°
angle BOC=180-48=132°
curcumfrence of a circle is given by:

π×diameter×(theta)/360

The length of arc BC will be given by:
length,circumference=π×d×132/360
=11/30πd units
=1.152d units
where d is the diameter of the circle
3 0
3 years ago
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