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Sladkaya [172]
4 years ago
7

Y=0.27x constant of proportionality

Mathematics
1 answer:
Nutka1998 [239]4 years ago
5 0

Answer:

0.02 gghgfvvvjkn ghjyfnj

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Can I get some help with this please.
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The y-intercept represent:

122,000 (1985) represents the starting population from when they began calculating the data.

Step-by-step explanation:

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Complete these activities. Consider the following information from Tiger Oil Company: By multiplying matrices, calculate the mat
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Given the matrix

\left[\begin{array}{cc}20&30\\15&5\\5&2\end{array}\right]

representing the number of thousands of gallons of regular and premium oil sold by the three stations of Tiger oil company and the matrix

\left[\begin{array}{c}500\\600\end{array}\right]

representing dolloars per thousands of gallons of regular and premium oil sold by Tiger oil company.

T<span>he matrix for total dollar volume of sales using matrix multiplication is given by:

\left[\begin{array}{cc}20&30\\15&5\\5&2\end{array}\right] \left[\begin{array}{c}500\\600\end{array}\right]=  \left[\begin{array}{c}20(500)+30(600)\\15(500)+5(600)\\5(500)+2(600)\end{array}\right]  \\  \\ = \left[\begin{array}{c}10000+18000\\7500+3000\\2500+1200\end{array}\right] =\left[\begin{array}{c}28000\\10500\\3700\end{array}\right]

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4 years ago
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27 millimeters = how many centimeters?
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A grasshopper sits on the first square of a 1×N board. He can jump over one or two squares and land on the next square. The gras
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Answer:

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You can start by imagining this scenario on a small scale, say 5 squares.

Assuming it starts on the first square, the grasshopper can cover the full 5 squares in 2 ways; either it can jump one square at a time, or it can jump all the way to the end and then backtrack. If it jumps one square at a time, it will take 4 hops to cover all 5 squares. If it jumps two squares at a time and then backtracks, it will take 2 jumps to cover the full 5 squares and then 2 to cover the 2 it missed, which is also 4. It will always be one less than the total amount of squares, since it begins on the first square and must touch the rest exactly once. Therefore, the smallest amount n is N-1. Hope this helps!

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