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Nesterboy [21]
3 years ago
14

Luis took out a 3 year loan for $4500 at a furniture store to be paid back

Mathematics
2 answers:
Iteru [2.4K]3 years ago
9 0

Answer : 21 --- APEX

SVETLANKA909090 [29]3 years ago
7 0

Answer:

$1252.13

Step-by-step explanation:

15.9% = .159

$4500 multiplied by .159 = $715.50

3 yrs = 36 months

36 months - 15 months = 21 months

21 months = 1.75 yrs.

$715.50 multiplied by 1.75 = $1252.13

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The price of gas increased from $2.20 per gallon on Monday to $2.31 per gallon on Tuesday. What is the percent of increase?
Oliga [24]
The percent increase would be about 55%
8 0
2 years ago
Help me please!!! Will mark the Brainliest!
raketka [301]

Answer:

48

Step-by-step explanation:

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3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval.
anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

f(x)=xe^{-\frac{x^{2}}{32} } , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

f(x)=xe^{-\frac{x^{2}}{32} }

Using the product rule, first derivative will be:

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} ) = 0

1-\frac{x^{2}}{16}=0

\frac{x^{2}}{16}=1

x^{2}=16

x = ±4

x can't be -4 because it is not in the interval [-2,8].

f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76

f(4)=4e^{-\frac{4^{2}}{32} }=2.42

f(8)=8e^{-\frac{8^{2}}{32} }=1.08

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0
3 years ago
Anyone know the answer to this question
Sloan [31]
You can do this! Start with 250 multiply by 0.15, since that is 15% Take that answer and subtract it from the original. let me know if you need more help
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3 years ago
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