Answer:
9
Step-by-step explanation:
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
7a + 6c + 9a - 15c
-- Look for all the 'a's 7a, 9a
-- Addum up 16a
-- Look for all the 'c's 6c, -15c
-- Addum up -9c
-- Write the results 16a - 9c
Step-by-step explanation:
You're given that ΔUVW is similar to ΔYZW. The tricky part is identifying which sides in ΔUVW correspond to which sides in ΔYZW.
The triangles share point W, so visually rotate one triangle around W until the two triangles align. That way, you can see that UW and ZW correspond to each other, and VW and YW correspond to each other.
Now you can find the scale:
VW / YW = 5/12
And you can write a proportion to find x:
UW / ZW = VW / YW
x / 64 = 5 / 12
x = 26 ⅔
Uhhhh i cant answer this without details
