Answer:
None of those answers are correct
Step-by-step explanation:
There are no real solutions
Let's solve your equation step-by-step.
2+2x−3
2x+3
=
3x+4
x+2
Step 1: Cross-multiply.
2+2x−3
2x+3
=
3x+4
x+2
(2+2x−3)*(x+2)=(3x+4)*(2x+3)
2x2+3x−2=6x2+17x+12
Step 2: Subtract 6x^2+17x+12 from both sides.
2x2+3x−2−(6x2+17x+12)=6x2+17x+12−(6x2+17x+12)
−4x2−14x−14=0
For this equation: a=-4, b=-14, c=-14
−4x2+−14x+−14=0
Step 3: Use quadratic formula with a=-4, b=-14, c=-14.
x=
−b±√b2−4ac
2a
x=
−(−14)±√(−14)2−4(−4)(−14)
2(−4)
x=
14±√−28
−8
Answer:
No real solutions.
Answer:
jkjkjkjkjkjk
Step-by-step explanation:
jkjkjkjkjkjkj
Answer:
1) (3,5) is the new point
2) P(-1,-4) U(-5,0) N (-2,1)
Step-by-step explanation:
hope this helps. good luck
Answer:
-| y | ≤ | -y |
Step-by-step explanation:
-| y | will be non-positive (may include 0). |-y| will be non-negative (may include 0). A non-positive number is always less than or equal to a non-negative number. They are only equal when both are zero.
Answer: 6^12 (or 2176782336)
When you multiply exponents with the same base, you add the exponents together. (e.g., x^m · x^n = x^m+n)
6^4 · 6^8 = 6^4+8 = 6^12