20 / 27 is the probability that a student chosen randomly from the class passed the test or completed the homework.
<u>Step-by-step explanation:</u>
To find the probability that a student chosen randomly from the class passed the test or complete the homework :
Let us take,
- Event A ⇒ a student chosen randomly from the class passed the test
- Event B ⇒ a student chosen randomly from the class complete the homework
We need to find out P (A or B) which is given by the formula,
⇒ P (A or B) = P(A) + P(B) - P(A∪B)
<u>From the given table of data,</u>
- The total number of students in the class = 27 students.
- The no.of students passed the test ⇒ 15+3 = 18 students.
P(A) = No.of students passed / Total students in the class
P(A) ⇒ 18 / 27
- The no.of students completed the homework ⇒ 15+2 = 17 students.
P(B) = No.of students completed the homework / Total students in the class
P(B) ⇒ 17 / 27
- The no.of students who passes the test and completed the homework = 15 students.
P(A∪B) = No.of students both passes and completes the homework / Total
P(A∪B) ⇒ 15 / 27
Therefore, to find out the P (A or B) :
⇒ P(A) + P(B) - P(A∪B)
⇒ (18 / 27) + (17 / 27) - (15 / 27)
⇒ 20 / 27
∴ The P (A or B) is 20/27.
Answer:
They sold 78 Hot Dogs and 156 Sodas
Step-by-step explanation:
Hope this Helps
The y-intercepts are
(0,0) and (5,0)
The equation of the quadratic function is
f(t) = at(t-5)
Solving for a
12 = a(3)(3-5)
a = -2
The equation of the quadractic function is
f(t) = -2t(t -5)
f(t) = -2t² + 10t<span />
Answer:
Step-by-step explanation:
Evaluate for x=5,y=−1
−3(5^2)+(2)(5)(−1)−(−1)^3
−3(5^2)+(2)(5)(−1)−(−1)^3
=−84
