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2 years ago

14 subtracted from a number, divided by 3, equals -8. Just write the equation if you want plzzzz

Mathematics

1 answer:

yuradex [85]2 years ago

5 0

Huh, alright?

The equation would be (n - 14) / 3 = -8

Hope that helps! :)

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The area enclosed by one shooting circle is 401.92 square yards. Write and solve a formula to find the radius of the shooting ci

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The formula for area in terms of radius is

... A = πr²

Solving this for r, we get

... A/π = r²

... r = √(A/π) . . . . . formula for the radius

For your given area, the radius is approximately

... r = √(401.92/3.14) = √128 = 8√2

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2 years ago

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Lilit [14]

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2 years ago

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disa [49]

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2 years ago

What is 2/3 Time 2/3

klasskru [66]

Answer:

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2 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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1 year ago