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kifflom [539]
3 years ago
15

A basket contains 9 blue ribbons, 7 red ribbons and 6 white ribbons. What is the probability that a ribbon selected at random wi

ll be red ?
Mathematics
2 answers:
quester [9]3 years ago
7 0
Probability=number of specific outcomes / total number of possible outcomes...

P(r)=7/(9+7+6)

P(r)=7/22  ( ≈31.82%)
serious [3.7K]3 years ago
4 0
Add 7+9+6 then convert to percent 
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Please help!<br><br> (ignore the answer I chose)
Andrei [34K]
The numerator factors as (t-8)(t+4), so the whole thing is (t-8)(t+4)/(t-8). Now we can cancel the t-8 AS LONG as t isn't equal to 8, otherwise, we are canceling a zero from both numerator and denominator which is invalid. What is left is t+4.

So your choice was right.
5 0
3 years ago
Which best describes a way in which Naturalism differs from Realism?
gtnhenbr [62]
The correct is a characteristic are idealized
7 0
3 years ago
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

now, we can use factor formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can use above formula

we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

27x^3-1=(3x-1)(9x^2+3x+1)=0

and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

now, we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can plug values

and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

5 0
3 years ago
Simplify -8(6m-7) using distributive form
Andreyy89

Answer:    -48m + 56

Step-by-step explanation:

-8x 6m= -48m

-8x-7= 56

8 0
3 years ago
Read 2 more answers
A system of equations is shown below: n = 3m + 5 n − 2m = 3 What is the solution, in the form (m, n), to the system of equations
marshall27 [118]
n=3m+5 \\&#10;n-2m=3 \\ \\&#10;\hbox{substitute 3m+5 for n in the second equation:} \\&#10;3m+5-2m=3 \\&#10;m+5=3 \\&#10;m=3-5 \\&#10;m=-2 \\ \\&#10;n=3m+5 \\&#10;n=3 \times (-2)+5 \\&#10;n=-6+5 \\&#10;n=-1 \\ \\&#10;(m,n)=(-2,-1)

The answer is C.
4 0
3 years ago
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