Answer:
(c), 0.75
Step-by-step explanation:
It is given that, the probability of boy is same as the probability of girl.
Number of children family plans to have = 3
Consider, B be the event that represents that child is a boy
G be the event that represents that child is a girl.
The simple events for the provided case could be written as:
S = {(GGG, BBB, GBB, BGB, BBG, BBG, GBG, GGB)}
From above simple event, it is clear that
P(3 boys) = 1/8 and P(3 Girls) = 1/8
Thus, the probability of having at least one boy and at least one girl can be calculated as:
![Probability = 1- (\frac{1}{8} + \frac{1}{8} ) = \frac{6}{8} =\frac{3}{4}](https://tex.z-dn.net/?f=Probability%20%3D%201-%20%28%5Cfrac%7B1%7D%7B8%7D%20%2B%20%5Cfrac%7B1%7D%7B8%7D%20%29%20%3D%20%5Cfrac%7B6%7D%7B8%7D%20%3D%5Cfrac%7B3%7D%7B4%7D)
Thus, the required probability is 0.75.
Hence, the correct option is (c), 0.75