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boyakko [2]
3 years ago
9

Can somebody help with my math homework?

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

Answer:

hi i can

Step-by-step explanation:

just cross multiply its easy

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A model rocket is launched directly upward at a speed of 50 meters per second from a height of 8 meters. The function f(t)=−4.9t
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Answer:

t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36

t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158

And since the time can't be negative we have that:

t= 10.36 seconds

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

Step-by-step explanation:

For this case we have the function of the height in terms of the time givenby:

h(t) = -4.9t^2 +50 t+8

And we want to known when the rockect hit the ground and for this case we need to solve the equation h=0

-4.9t^2 +50 t+8 =0

And as we can see we have a quadratic equation like this one:

ax^2 +bx+c

Where: a =-4.9 , b =50 c =8

And the general solutions are given by:

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

If we replace the values that we have we got:

t=\frac{-50 -\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= 10.36

t=\frac{-50 +\sqrt{(50)^2 -4(-4.9)(8)}}{2*(-4.9)}= -0.158

And since the time can't be negative we have that:

t= 10.36 seconds

So the answer for this case would be after 10.36 seconds the rocket will hit the ground

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Step-by-step explanation:

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