Answer:
x=5.37 cm
Step-by-step explanation:
we know that
The volume of the box is
where
B is the area of the base of the box
h is the height of the box
<em>Box 1</em>
we have that
The area of the base is
The volume of the Box 1
is equal to
<em>Box 2</em>
we have that
The area of the base is
The volume of the Box 2
is equal to
![V_2=[(x+1)^2(x+2)]\ cm^3](https://tex.z-dn.net/?f=V_2%3D%5B%28x%2B1%29%5E2%28x%2B2%29%5D%5C%20cm%5E3)
![V_2=[(x^2+2x+1)(x+2)]\ cm^3](https://tex.z-dn.net/?f=V_2%3D%5B%28x%5E2%2B2x%2B1%29%28x%2B2%29%5D%5C%20cm%5E3)
Equate the equation of Volume 1 to the equation of Volume 2
Solve the quadratic equation by graphing
using a graphing tool
The solution is x=5.37 cm
see the attached figure
<span>given tan theta 4/3 and sin (-4/5), find cos theta
cos theta-3/5</span>
Answer:
11 sq.ft
Step-by-step explanation:
∅= 80×π/180= 4π/9
area= 1/2 × r²× ∅
= 1/2 × 16 × ∅
= 8∅
=8×(4π/9)
= 32π/9
= 11.17 ~11
Answer:
use a median , mean and median mode calculator there are plenty online...i don't know for sure this question but you can use those calculators it will generate it for you
Step-by-step explanation:
Divide $1,137.50 by 350 to see out how much each book costs. Then divide $1,500 by 350 to see how much the school should add to the price of each agenda book to make the total profit. So the answer should be: (1137.50/350)+(1500/350) = minimum price
