Answer:
B. 3.
Step-by-step explanation:
OK lets try again.
The slope of the secant = slope of the tangent at a certain point ( The Mean Value Theorem).
Slope of the secant = f(5) - f(2) / (5 - 2)
= [(25-3) / (5-1) - (4-3) / (2-1)] / 3
= (22/4 - 1) / 3
= 9/2 / 3
= 9/6
= 3/2.
The derivative at c = the slope of the tangent at c.
Finding the derivative:
f'(x) = [2x(x - 1) - (x^2 - 3) ]/ (x - 1)^2 (where x = c).
= (x^2 - 2x + 3)/ (x - 1)^2 = the slope.
So equating the slopes:
(x^2 - 2x + 3) / (x - 1)^2 = 3/2
2x^2 - 4x + 6 = 3x^2 - 6x + 3
x^2 - 2x - 3 = 0
(x - 3)(x + 1) = 90
x = 3 , -1
x can't be -1 because we are working between the values 2 and 5 so
x = c = 3.
7x-35<2x-10 distribut it
7x-2x<-10+35 collect like them
5x<25 divide both side by 5
x<5
Answer: m∠ATC = 54°
Step-by-step explanation:
Ok, we know that:
m∠ATB = 20° and m∠BTD = 72°
then we must have that the angle between A and D, is equal to the sum of the angles between A and B, and B and D, or:
m∠ATD = m∠ATB + m∠BTD = 20° + 72° = 92°
Now, we also know that m∠CTD = 38°
And the angle:
m∠ATC will be equal to the angle between A and D, minus the angle between C and D, or:
m∠ATC = m∠ATD - m∠CTD = 92° - 38° = 54°
Answer:
it belongs to rational number......
