For the answer to the question above, I'll show my solution on how you can solve your problem.
AC² + BC² = AB²
<span>5² + 12² = AB² </span>
<span>25 + 144 = AB² </span>
<span>169 = AB² </span>
<span>13 = AB </span>
<span>Triangle ABC is proportional to triangle ADB. </span>
<span><u>AC </u>= <u>AB </u></span>
<span>AB AD </span>
<span><u>5</u> = <u>13 </u></span>
<span>13 AD </span>
<span>5AD = 169 </span>
<span>AD = 169/5 </span>
<span>AD = 33.8 </span>
<span>AD = AC + CD </span>
<span>33.8 = 5 + CD
</span>So the answer is
<span>CD = 28.8 </span>
Answer:
can u plz make a good picture to solve I can't see good
Step-by-step explanation:
and thanks
Answer:
So then the best option would be:
a. 1/25
Step-by-step explanation:
For this case we assume that the sample space for the numbers is :
![S_1= [A,B,C,D,E]](https://tex.z-dn.net/?f=%20S_1%3D%20%5BA%2CB%2CC%2CD%2CE%5D)
And the sample space for the numbers is:
![S_2 =[1,2,3,4,5]](https://tex.z-dn.net/?f=%20S_2%20%3D%5B1%2C2%2C3%2C4%2C5%5D)
Both sampling spaces with a size of 5.
We define the following events:
A="We select a 2 from the numbers"
B= "We select a E from the letters"
We can find the individual probabilities for each event like this:
And assuming independence we can find the probability required like this:
The last probability is the probability of obtain obtain a 2 AND an E
So then the best option would be:
a. 1/25
Answer:
4 units left
Step-by-step explanation:
Answer: 9 L
Step-by-step explanation:
Given
The dimension of the rectangular container is 
It is filled with 
of the height
Water present in the container
Also, 
Now, half of the water is poured out
So, half is left
Thus, 9 L of water is left in the container
