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Musya8 [376]
3 years ago
15

What two decimals are equivalent to 5.300

Mathematics
2 answers:
vredina [299]3 years ago
5 0
5.30 and 5.3 are equivalent to 5.300.
You see, if there is a zero at the end of each decimals, that is nothing. 
Zeroes or nothing.
But if it were to be a number, for example:
5.3003, it would be different.
5.3000000000000000000000000000000000
is the same thing to 5.3
Ask me if you don't understand.
I hope it helped...
kaheart [24]3 years ago
5 0

Two or more decimal numbers are said to be equivalent decimals, when they name the same value (or same amount). For example, the decimals: 0.2 = 0.20 = 0.200 = 0.2000 etc. Thus by successive addition of zeros after the decimal part of the number after the decimal point means the same number and hence are equivalent. Therefore, the decimals: 5.3, 5.30, 5.300, 5.3000 etc are all equivalent.

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Lou’s Shoes is having its annual Flag Day Sale and is offering a 25% discount on all regularly priced shoes. Kayla spends $13.50
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The easiest way to think of these is to put them in terms of percentages.  Obviously, if you are SAVING 25%, you are SPENDING 75%.  So if she SPENDS 13.50, we can easily use the 75% in an equation. $13.50 = .75x, with x being what the shoes cost originally.  The .75 indicates that she is spending 75% of what the original cost is. You don't have any examples to pick from, but this is the best way to explain what one of the equations could be.  You could also base it on money saved, but the equation is not quite as neat.
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4 years ago
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If A=(0,0) and B=(8,2), what is the length of AB
NeX [460]

Answer:

\boxed{\sf Distance_{AB}= 8.24 \ units }

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,

<em>Distance Formula:- </em>

\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}

Therefore on substituting the respective values ,we can find the Distance as ,

\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}

<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>

\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}

Square the numbers inside the squareroot ,

\sf\longrightarrow Distance =\sqrt{ 64 + 4}

Add the numbers inside the squareroot ,

\sf\longrightarrow Distance = \sqrt{68}

Find the value of squareroot,

\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}

<u>Hence</u><u> the</u><u> </u><u>distance</u><u> between</u><u> the</u><u> two</u><u> points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>2</u><u>4</u><u> </u><u>units </u><u>.</u>

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3 years ago
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garri49 [273]

24.95 times 3 is $74.85

Your answer is $74.85

<em>Hope this helps!</em>

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