Answer:
what grade yo.u in
Step-by-step explanation:
..
Answer:
- x < 2.5
- x > 2.5
Step-by-step explanation:
One way to do this is to try a number for x and see if it makes the inequality true. A suitable number here is x=0. This value of x is less than 2.5.
<h3>1.</h3>
For x=0, you have ...
5 > -5 . . . . . true; the solution space is x < 2.5
__
<h3>2.</h3>
For x=0, you have ...
-25 > -5(2.5)
-25 > -12.5 . . . . . false; the solution space is x > 2.5
_____
<em>Alternate solution</em>
<h3>1.</h3>
Subtract 5:
-4x > -10
Divide by -4
x < 2.5
__
<h3>2.</h3>
Divide by -5:
5 < x +2.5
Subtract 2.5
2.5 < x
x > 2.5
<span>52.6378901393 should be correct.</span>
Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:5n+6
Step-by-step explanation :an=a1+d(n-1)
=1+(-5)(n-1) or 1+-5n+5
an=-5n+6
