<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer:
10=16[ by cost]
Step-by-step explanation: the cost of 10 chairs is x.
the cost 16 chairs is also x. 10x = 16x
4x is loss.
Profit or Gain = Selling price – Cost price. Loss = Cost price – Selling price. Profit Percentage = [Profit/C.P.]×100. Percentage Loss = [Loss/C.P.]×100.
In simple way, we can say that sp- cp[ when it is a gain], cp -sp[ when it is a loss]. here it is a loss as well as a gain. so do both according to the formula
20 and 21 is your answer
20 + 21 = 41
hope this helps
Answer:
Just Transposition...
Step-by-step explanation:
12×7=84=d
92-49=43=e
28+57=85=f
96÷16=6=g
11×8=88=h
95+5-29=100-29=71=I
55-6+21=70=j
88+8÷4=96÷4=16=k
19+24-97=-97-43=54=m
-20+17+61=61+3=64=n
hope it helps
Answer:
A=2(1+2)a2=2·(1+2)·22≈19.31371
Step-by-step explanation:
hope this helps!
