The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
x= 8 inches
Step-by-step explanation:
you left out the other lengths but since i had this same question once, the other lengths are 12 and 2-
dimensions of the box:
12 in x 2 in x ?
=272 square inches
and we know that there are 6 faces
area= 2 *(12 * 2) + 2 *(2*x) + 2 *(12*x)
area = 272 sq. in. = 48 + 4x + 24x
272 = 48 + 28x
272 - 48 = 28x
224 = 28x
x = 8 inches
good luck :)
i hope this helps
brainliest would be highly appreciated
have a nice day!
First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest
(4^8)w This is the answer
