The solutions or roots to this equation is found by solving for x. We can do this a couple ways either by FOIL or quad formula
3x^2+6x+6=0
3(x^2+2x+2)=0
x^2+2x+2=0 we cant FOIL this out so we use the quad formula
x= [(-b+\-sqrt(b^2-4ac))/2a]
x= -2+\- sqrt(4-4(1)(2))/2(1)
x= -1 +i , -1 - i
So we have complex roots since our quad formula returned a negative number. Whenever the quad formula answer is positive we have two roots/solutions, when it is zero we have one root/solution, and whenever it is negative we have Complex roots/solutions
Hope this helps. Any questions please just ask. Thank you.
Answer:
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Step-by-step explanation:
Answer:
i can't answer this but i can tell you this
The general form of an absolute value function is f(x)=a|x-h|+k. From this form, we can draw graphs.
y = a(x – h)2 + k, where (h, k) is the vertex. ... In the vertex form of the quadratic, the fact that (h, k) is the vertex makes sense if you think about it for a minute, and it's because the quantity "x – h" is squared, so its value is always zero or greater; being squared, it can never be negative.
Step-by-step explanation:
it is not the answer but i hope it helps:)
All triangles add up to 180 degrees, so you do 180 - 23 - 18 which is 139
The discontinuity occurs when the denominator is equal to zero, as it has "infinite" slope, and thus is not a real value or point.
x^2+x-12
x^2+4x-3x-12
x(x+4)-3(x+4)
(x-3)(x+4)
So discontinuities occur when x=-4 and x=3
