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jok3333 [9.3K]
3 years ago
7

What does it mean to be "in the black"

Mathematics
2 answers:
horsena [70]3 years ago
7 0

Answer:

to be unaware

Step-by-step explanation:

elena55 [62]3 years ago
7 0
The expression “in the black” is used to refer to a company’s profitability and current financial health. When a company is in the black, it has positive earnings, is financially solvent.
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In winter, the price of apples suddenly went up by $0.75 per pound. Sam bought 3 pounds of apples at the new price for a total o
dmitriy555 [2]
P represents the original per pound price3p represents the cost of three pounds 3p + 3(0.75) = 5.88           multiply3p + 2.25 = 5.88               subtract 2.55 from both sides3p = 3.63                          divide both sidesby 3p = 1.21 The original price was $1.21 per pound. 1.21 = 0.751.963(1.96)5.88
5 0
4 years ago
Gabriel and his friends went into a restaurant and they want to buy some chicken wings and tacos. Each chicken wing costs $0.50
Musya8 [376]
The chicken wings costs 15 $ whiles the tacos cost8$
7 0
3 years ago
Solve for x 6x^2=2x-1
leva [86]

Answer:

\displaystyle x=\frac{1\pm i\sqrt{5}}{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

6x² = 2x - 1

<u>Step 2: Rewrite</u>

  1. Subtract 2x on both sides:                    6x² - 2x = -1
  2. Add 1 to both sides:                               6x² - 2x + 1 = 0

<u>Step 3: Identify Variables</u>

a = 6

b = -2

c = 1

<u>Step 4: Solve for </u><em><u>x</u></em>

  1. Substitute [QF]:                       \displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(6)(1)} }{2(6)}
  2. Exponents:                              \displaystyle x=\frac{2\pm\sqrt{4-4(6)(1)} }{2(6)}
  3. Multiplication:                         \displaystyle x=\frac{2\pm\sqrt{4-24} }{12}
  4. (Square Root) Subtract:         \displaystyle x=\frac{2\pm\sqrt{-20} }{12}
  5. Factor:                                    \displaystyle x=\frac{2\pm \sqrt{-1} \sqrt{20} }{12}
  6. Simplify:                                 \displaystyle x=\frac{2\pm 2i\sqrt{5} }{12}
  7. Factor GCF:                           \displaystyle x=\frac{2(1\pm i\sqrt{5} )}{12}
  8. Simplify:                                 \displaystyle x=\frac{1\pm i\sqrt{5}}{6}
3 0
3 years ago
Regrouping add 64 and 9 to show
In-s [12.5K]
     73 I hope i helped with the *quashins

5 0
3 years ago
Read 2 more answers
Plsss help i need this
kykrilka [37]

Answer:

Step-by-step explanation:

A.70

B. 121

C. 200

5 0
3 years ago
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