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3 years ago

Help i need the answer ASAP

Mathematics

1 answer:

musickatia [10]3 years ago

6 0

Answer:

(4, -1/4)

Step-by-step explanation:

Add both the equations.

The y-terms will cancel.

You will get,

x/4+3x/4=5/8+27/8

or,x=32/8=4

Now, substitute the value of x in any one of the equation and you'll get the value of y,like

(Taking equation 1),

4/4+3y/2=5/8

or,3y/2=5/8-1=-3/8

or,y=(-3/8)x(2/3)

or,y=-1/4

So,x=4 and y=-1/4

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Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter

jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

$\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\$

since s(t) is the arc length for r(t), which is define as

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt$

if we substitute the value of r'(t) we arrive at

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\$

$s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }$

substituting the value of t in to the given vector equation we have

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

4 0

4 years ago

on marks first day, he ran 5 laps without stopping after several weeks of training he ran 9 weeks without stopping. what is the

tino4ka555 [31]

The percentage increase from 5 laps of race on the first day to 9 laps after several weeks is 80%

<h3>How to determine the percentage increase?</h3>

The distance ran are given as:

Initial = 5 laps

Final= 9 laps

The percentage increase is calculated using:

Percentage = (Final - Initial)/Initial

So, we have:

Percentage = (9 - 5)/5

Evaluate

Percentage = 0.8

Express as percentage

Percentage = 80%

Hence, the percentage increase is 80%

Read more about percentage increase at:

brainly.com/question/11360390

8 0

2 years ago

Direction: Answer the following problem sets. Please include what is the given, asked, formula, solution and final answer with u

olga2289 [7]

Answer:

7.5s

1.6666 repeating or 1.67 m/s²

Step-by-step explanation:

the equation you have to use is Vfinal=Vstart+acceleration•time

(I'm gonna simplify to Vf=Vs+at)

so you gotta rework it for the two equations

for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at

then divide acceleration on both sides to get t=(Vf–Vs)/a

for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)

so you the plug in

(I don't put the units in to the problem unless needed)

1. t=(Vf–Vs)/a to t=(0–30)/-4.0

t= -30/-4.0

t=7.5 seconds

2. a=(Vf–Vs)/t to a=(10–0)/6.0

a= 10/6.0

a= 1.67m/s²

(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)

8 0

3 years ago

H= ? 1.8 m 6m 60m Looking for meters!

leva [86]

Answer:

Step-by-step explanation:

7 0

2 years ago

70° x 82° r r 6 - - 4)º an 160° (2y - 40 HELP ASAP

natulia [17]

Answer:

Step-by-step explanation:

x + 70 = 180 {Linear pair}

x = 180 - 70

x = 110

y + 82 = 180 {linear pair}

y = 180 -82

y = 98

x - 4 = 110 - 4 = 106

2y - 40 = 2*98 - 40

= 196 - 40

= 156

4 0

2 years ago