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svetlana [45]
3 years ago
13

Given: ∠V ≅ ∠Y, bisects ∠VWY. Prove: ∆VWZ ≅ ∆YWZ Look at the figure. Which postulate or theorem proves the triangles are congrue

nt? SSS Postulate AAS Theorem ASA Postulate SAS Postulate
Mathematics
1 answer:
Maru [420]3 years ago
8 0

Answer:

AAS

Step-by-step explanation:

We say Angle Angle side Similarty if the two conscutive angles of the triangle are congrent or epual

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Solving special systems.
goldfiish [28.3K]

Answer:

Step-by-step explanation:

it has no solutions b/c the lines are parallel...but at a different offset.. so they never cross

8 0
2 years ago
4+(−1 2/3) i don't get how to this cuz there aren't two fractions, just one.
kenny6666 [7]

Answer:

2 1/3

Step-by-step explanation:

4 + ( -1 2/3)

= 4 - 1 2/3

=  4 - 5/3

= 12/2 - 5/3

= 7/3

= 2 1/3



5 0
2 years ago
Can someone help me with this, I don’t understand.
Tema [17]
180-(83+53)=44
That will be the answer
3 0
3 years ago
Can you please help me ​
mylen [45]

Answer:

3

Step-by-step explanation:

please remember when dividing letters or numbers of the same base then their exponents will be minused.

4 0
3 years ago
Factor 2x2 + 7x + 3. <br> (2x + 2)(x + 1) <br> (2x + 3)(x + 1) (2x + 1)(x + 3)
maks197457 [2]
<h3>Answer:</h3>

(2x + 1)(x + 3)

<h3>Step-by-step explanation:</h3>

It is probably easier to try the answer choices than to try to factor the expression yourself.

(2x + 2)(x + 1) = 2x² +4x +2

(2x + 3)(x + 1) = 2x² +5x +3

(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice

_____

<em>Constructed solution</em>

If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.

... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7

Now, rewrite the x term using the sum of these numbers.

... 2x² +(1 +6)x +3

... 2x +x +6x +3 . . . . eliminate parentheses

... (2x +x) +(6x +3) . . . . group pairs of terms

... x(2x +1) +3(2x +1) . . . . factor each pair

... (x +3)(2x +1) . . . . . . matches the last selection

6 0
2 years ago
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