Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:

Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
3 possible solutions to the equation 2x+y=10 are shown below:
X= 3, Y=4
(3*2+4=10)
X= 1, Y=8
(1*2+8=10)
X=4, Y=2
(4*2+2=10)
Hope this helps! :)
The answer should be: 5/8 x 1/10 = 1/16.
In this question, we have to find the complement and supplement of the given angles .
Complementary angles are those angles whose sum is 90 degree and supplementary angles are those angles whose sum is 180 degree.
So to find the complement and supplement angles, we need to subtract the given angles from pi/2 and pi respectively .
a.

b.
