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finlep [7]
3 years ago
6

A. x = 2, y =6 B. x = 2, y =3 C. x =-2, y =3 D. x = -3, y =2

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

the answer is

A. X=2, y=6

Step-by-step explanation:

use substitution

y= 6 so,

y-3 = 6-3 which is 3

and y-1 = 6-1 which is 5

now for x

x=2

x+3= 2+3 which is 5

2x-1= 2(2)-1

2 times 2 is 4

4-1 = 3


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Which expression is equivalent to n2 + 26n + 88 for all values of n?
Lelechka [254]

Answer:

Option B is correct.

The expression which is equivalent to  n^2+26n+88  is; (n+22)(n+4)

Explanation:

Given the equation: n^2+26n+88 for all values of n.

The quadratic equation in this form; ax^2+bx+c =0

First find two numbers that multiply to give ac and add to give b.

From the given equation;

a =1 , b = 26 and c =88

then,

the two number that multiply to give ac =88 is, 22 or 4

and they add up to give b=26 (i.e 22+4)

Now, rewrite the middle term i.e 26n with 22n and 4n , we have

n^2+22n+4n+88=0

Now, factor the first two terms and last two terms,

n(n+22)+4(n+22)

we see that (n+22) is common to both terms so, we have;

(n+22)(n+4)

Therefore, the expression (n+22)(n+4) is equivalent to  n^2+26n+88

Check:

(n+4)(n+22) = n\cdot n+ 22n+4n+88=n^2+26n+88   [ True]



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