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ArbitrLikvidat [17]
4 years ago
6

Andrew sells 10 paintings each day at the state fair. The expression below represents the total amount of money that Andrew earn

ed at the fair where x is the number of days after the first day of the fair. Interpret the meaning of each term in the expression. The first term indicates that the 10 paintings were each sold at $50 per additional day of the fair. The second term indicates that the 10 paintings were each sold at $55 on the first day of the fair. The first term indicates that the 10 paintings were each sold at $50 on the first day of fair. The second term indicates that the 10 paintings were each sold at $55 per additional day of the fair. The first term indicates that the 10 paintings were each sold at $55 on the first day of fair. The second term indicates that the 10 paintings were each sold at $50 per additional day of the fair. The first term indicates that the 10 paintings were each sold at $55 per additional day of the fair. The second term indicates that the 10 paintings were each sold at $50 on the first day of the fair
Mathematics
2 answers:
geniusboy [140]4 years ago
8 0

This is really confusing im not sure you wrote it correctly

xxTIMURxx [149]4 years ago
8 0

Answer:

c

Step-by-step explanation:

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Answer:

a) 0.975

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Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 75

Standard deviation = 5

We also have that since the normal distribution is symmetric, 50% of the measures are below the mean and 50% are above.

a. The relative frequency of rates less than 85 using the 68-95-99.7 rule is

85 is two standard deviations above the mean.

So all the 50% below the mean is below 85

And of the 50% above the mean, 95% is less than 85. So

0.5 + 0.95*0.5 = 0.975

b. The relative frequency of rates greater than 80 using the 68-95-99.7 rule is

80 is one standard deviations above the mean.

Of the 50% above the mean, 68% is less than 80. So 100-68 = 32% is more than 80.

0.32*0.5 = 0.16.

c. The relative frequency of rates between 65 and 75 using the 68-95-99.7 rule is

Within the mean and two standard deviations below the mean.

So 95% of 50%

0.95*0.5 = 0.475

6 0
4 years ago
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3 years ago
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8 0
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3 years ago
A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres
topjm [15]

Let U(t) denote the amount of uranium-238 in the reactor at time t. As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

\dfrac{\mathrm dU}{\mathrm dt}=-kU

where k>0 is constant. Separating variables and integrating both sides gives

\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}

Suppose we start some amount u. This means that at time t=0 we have U(0)=u, so that

u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if t is taken to be in years) for some starting amount u,

0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}

The half-life is the time t_{1/2} it takes for the starting amount u to decay to half, 0.5u:

0.5u=ue^{-kt_{1/2}}\implies t_{1/2}=-\dfrac{\ln(0.5)}k=\dfrac{10\ln2}{\ln(0.9997)}

or about 23,101 years. Notice that it doesn't matter what the actual starting amount is, the half-life is independent of that.

7 0
3 years ago
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