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Novosadov [1.4K]
3 years ago
15

12 x − 8 y = 24 6 x − y = 21

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer: x=4

              y=3

Step-by-step explanation:

12x-8y=24

6x-y=21

---------------------

y=6x-21

12x-8(6x-21)=24

12x-48x+168=24

-36x=-144

x=144/36

x=4

y=24-21

y=3

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Consider all angles whose reference angle is 45° with terminal sides not in Quadrant I.The angles that share the same cosine val
Oksana_A [137]

Solution:

As we know reference angle is smallest angle between terminal side and X axis.

As cosine 45 ° is always positive in first and fourth quadrant.

i.e CosФ, Cos (-Ф) or Cos(2π - Ф) have same value.

As, Cos 45°, Cos (-45°) or Cos ( 360° - 45°)= Cos 315°are same.

So, Angles that share the same Cosine value as Cos 45° have same terminal sides  will be in Quadrant IV having value Either Cos (-45°) or Cos (315°).

Also, Cos 45° = Sin 45° or Sin 135° i.e terminal side in first Quadrant or second Quadrant.



6 0
3 years ago
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Figure PQRS is a parallelogram. The expressions represent the measures of the angles in degrees. What is the value of x? 5 10 20
Galina-37 [17]
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5 0
3 years ago
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What is the value of 3.5 (11) + 1.9 (11) + 1.6 (11)?
irina1246 [14]

Answer:

77

Step-by-step explanation:

3.5(11)+1.9(11)+1.6(11)

3.5(11)=38.5

1.9(11)=20.9

1.6(11)=17.6

38.5+20.9+17.6

77

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3 years ago
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7 0
3 years ago
Read 2 more answers
?
yanalaym [24]

Answer:

A=\pi \frac{d^2}{4}

Step-by-step explanation:

The typical equation for the area of a circle is A=\pi r^2. Since the answer choices are in terms of <em>d</em>, the diameter of the circle, you will need to find <em>r</em> in terms of <em>d</em>.

To find <em>r</em> in terms of <em>d</em>, you know that the diameter of a circle is two times its radius. As an equation, this is

d=2r, or solving for <em>r</em>,

r = \frac{d}{2}.

Now that you have an equation for <em>r</em> in terms of <em>d, </em>you can substitute <em>r</em> with \frac{d}{2} from the original equation.

A=\pi r^2

A=\pi (\frac{d}{2})^2

A=\pi \frac{d^2}{4}

4 0
3 years ago
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