X²+15x+36<0
at first solve quadratic equation
D=b²-4ac= 225-4*1*36= 81
x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3
we can write x²+15x+36<0 as (x+12)(x+3)<0
(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set
or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality
Answer:
Look below
Step-by-step explanation:
372,000 = 372,000
372,000 = 300,000 + 70,000 + 2,000
Hopefully this helps you
pls mark brainlest
Answer:
4
Step-by-step explanation:
First, use the distributive property: 2x+16=4x+8
Second, move +8 to the other side(and turn it negative): 2x+8= 4x
Do the same for +2x: 8=2x
divide both sides by 2: 4=x
I believe the answer should be C.
I am not sure how to do that method... I only know this. (heehee)
Answer:
100,000
Step-by-step explanation:
The 9 is in the hundredth thousand place
