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d1i1m1o1n [39]
3 years ago
12

The goal of a benefit concert is to collect 50,000 cans of food. Food is collected at each entrance to the concert. The voluntee

rs collect 15,682 cans at entrance A; 18,940 cans at entrance B; 16,114 cans at entrance C; and 12,468 cans at entrance D. Did they collect more or fewer cans than desired? How many more or fewer?
Mathematics
2 answers:
Gennadij [26K]3 years ago
4 0

Answer:

They collected 63,204. Which is more. 13,204 than their intended goal.

Step-by-step explanation:

15,682+18,940+16,114+12,468=63,204


63,204-50,000=13,204

Hope this helped.

Readme [11.4K]3 years ago
4 0

Answer:

They collected 13204 more than they desired.

Step-by-step explanation:

Calculate the sum of cans collected at each entrance:

Total=A+B+C+D\\Total=15682+18940+16114+12468\\Total=63204

They collected more than what they had planned. To calculate how much more, the 50000 should be subtracted from the number of cans that were actually collected:

Excess=63204-50000=13204

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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3 years ago
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Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through t
noname [10]

Answer:

a.y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

by(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

Step-by-step explanation:

1.y''-4y'+4y=6x e^{2x}

Auxillary equation

D^2-4D+ 4=0

(D-2)(D-2)=0

D=2,2

Then complementary solution =C_1e^{2x}+C_2xe^{2x}

Particular solution =\frac{6 xe^{2x}}{(D-2)^2}

D is replace by D+2 then we get

P.I=\frac{6xe^{2x}}{0}

P.I=\frac{e^{ax}}{D+a} \cdot .V

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P.I=\frac}x^3e^{2x}

By integrating two times

Hence, the general solution

y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

b.y''+9y=5 cos x-7 sin x

Auxillary equation

D^2+9=0

D=\pm 3i

C.F=c_1 cos 3x+ c_2sin 3x

P.I=\frac{5 cos x-7 sin x}{D^2+9}

P.I=\frac{sin ax}{D^2+bD +C}

Then  D square is replace by -a square

D^2 is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

4 0
3 years ago
find the time in which a train of length 132 M will cross and electric post if the speed of the train be to 6.4 km /hour​
katrin [286]

Answer:

It will take the train 1.2375 minutes to pass the tunnel

Step-by-step explanation:

Mathematically, we know that ;

time = distance/ speed

The distance here is the length of the train which is 132 m ; we can convert this to km by dividing by 1000

We have this as 132/1000 = 0.132 km

So, we have the time as;

0.132 km/6.4 km/hr = 0.020625 hr

Mathematically, we know that 60 minutes make an hour;

so we have

0.020625 * 60 = 1.2375 minutes

3 0
3 years ago
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