If altitude drawn from vertex A is also the median, the triangle is isosceles such that AB = AC and BC is the base. Hence this altitude is also the angle bisector. – If median drawn from vertex A is also the angle bisector, the triangle is isosceles such that AB = AC and BC is the base.
Answer:
The line of best fit for your specific question is a linear equation.
Step-by-step explanation:
A linear equation has a constant rate of growth/decline and the growth/decline rate will never change in an linear equation.
If you draw a line that approximately splits between all the data plots, you will notice the line you drew is very close to the data points.
If the data plots was a quadratic, it would be very hard to draw a line of best fit.
Linear equations can easily be identified in a graph because it is a straight line.
Perhaps insert this equation into your graphing calculator or other graphing software online (like Desmos): y = 3x+2
A quadratic equation can also easily be identified in a graph because, in most cases, it looks like a U.
Take these examples: y =
or y=
I’m pretty sure the slope would be, Y=4.67.. I hope you get it right!
when you dive the fractions
2/3 = 0.666666
6/10=0.6000
4/5 = 0.80
6/5 = 1.2
so the answer would be 2/3
Recognize that "( ) over 2^3" means ( ) • 2^-3. Use the rule of exponents
.. (a^b)^c = a^(b•c)
= 2^-16•5^10•19^-2 • 5^-8*2^-12 • 2^28
Now, you can use the rule of exponents
.. (a^b)*(a^c) = a^(b+c)
= 2^(-16 -12 +28) • 5^(10 -8) • 19^-2
= 5^2 • 19^-2
= 5^2 / 19^2
= 25/361