Answer:
That shows no relationship
Answer:
years 1–4: 62.4 bass per year
years 5–8: 67.6 bass per year
Step-by-step explanation:
If the population in year n is ...
p(n) = 3000·1.02^n
then the average rate of change from year 1 to year 4 is ...
(p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4
The average rate of change for years 1–4 is 62.4 bass per year.
For years 5–8, the rate of change is similarly computed:
(p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6
The average rate of change for years 5–8 is 67.6 bass per year.
Answer: <em><u>1/9, 0.48, 0.6, 2/3, 5/6</u></em>
Step-by-step explanation:
Order these numbers: 0.6 , 2/3 , 5/6 , 1/9 , 0.48
0.6 = 0.6
2/3 = 0.6666666....
5/6 = 0.8333333....
1/9 = 0.111111.....
0.48 = 0.48
In order, it will go 1/9, 0.48, 0.6, 2/3, 5/6
Answer:
feel like its C
Step-by-step explanation:
