Answer:
What do you need help with?
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
Let's plug your functions f(x)=x^2-2x and g(x)=6x+4 into (f+g)(x)=0 and then solve your equation for x.
So (f+g)(x) means f(x)+g(x).
So (f+g)(x)=x^2+4x+4
Now we are solving (f+g)(x)=0 which means we are solve x^2+4x+4=0.
x^2+4x+4 is actually a perfect square and is equal to (x+2)^2.
So our equation is equivalent to solving (x+2)^2=0.
(x+2)^2=0 when x+2=0.
Subtracting 2 on both sides gives us x=-2.
Answer: (D) <em>bottom right graph</em>
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: f(x) = a(x - h)² + k, where
- (h, k) is the vertex
- |a| is the vertical stretch
- sign of "a" determines the direction of the parabola
Given g(x) = (x - 3)² - 5
- vertex (h, k) = (3, -5)
- vertical stretch |a| = 1
- sign of "a" is positive so parabola points up
The only graph that satisfies all of these conditions is the bottom right.
Answer:
600 students, because 35%=0.35. When you multiply 0.35 by 600 you get 210.
