If the sound of the quietest noise a person can hear is x, then the sound of the normal conversation is x(10^6). Also, the sound of the jet at takeoff is x(10^14). When we divide x(10^14) by x(10^6), we get the answer that is equal to 10^8. Thus, the sound of jet at takeoff is 10^8 times that of the normal conversation.
Answer:
10000
Step-by-step explanation: