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Leokris [45]
4 years ago
6

X is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integer

s, then each of the following could be true EXCEPT
A. x = w
B. x > w
C. x/y is an integer
D. w/z is an integer
E. x/z is an integer
Mathematics
1 answer:
zlopas [31]4 years ago
8 0

Answer:

The answer is C.

Step-by-step explanation:

The key to solve the problem is the equation given

y = 2z         which means that<u> y is always an even number.</u>

For example:

let z = 1;       y  = 2(1)     y = 2;

let z = 2;      y  = 2(2)     y = 4;

let z = 3;      y  = 2(3)     y = 6;

And we know that for any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms.

For example:

Set of numbers: [1,2,3,4,5,6] ;

Sum of the set:  1+2+3+4+5+6 = 21 ;

Number of terms of the set: 6;

Therefore, 21 is not a multiple of 6.

But for any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms.

For example:

Set of numbers: [1,2,3,4,5,] ;

Sum of the set:  1+2+3+4+5 = 15 ;

Number of terms of the set: 5;

Therefore, 15 is a multiple of 5.

And that's why we know that if y is always an even number (y = 2z), the sum of the consecutive integers (x) is not a multiple of y, therefore x/y cannot be an integer.

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Angelina_Jolie [31]
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4 0
3 years ago
A box of candy bars costs $3.12. Each candy bar in the box costs $0.52. How many candy bars are in the box?
bulgar [2K]

Answer:

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Step-by-step explanation:

$3.12 (total)

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3.12=0.52b

divide on both sides

3.12/0.52

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3 years ago
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•••••
•••••
•••••
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7 0
3 years ago
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astra-53 [7]

Answer:

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Step-by-step explanation:

18-4

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÷2

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hoped this helped

5 0
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