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Leokris [45]
3 years ago
6

X is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integer

s, then each of the following could be true EXCEPT
A. x = w
B. x > w
C. x/y is an integer
D. w/z is an integer
E. x/z is an integer
Mathematics
1 answer:
zlopas [31]3 years ago
8 0

Answer:

The answer is C.

Step-by-step explanation:

The key to solve the problem is the equation given

y = 2z         which means that<u> y is always an even number.</u>

For example:

let z = 1;       y  = 2(1)     y = 2;

let z = 2;      y  = 2(2)     y = 4;

let z = 3;      y  = 2(3)     y = 6;

And we know that for any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms.

For example:

Set of numbers: [1,2,3,4,5,6] ;

Sum of the set:  1+2+3+4+5+6 = 21 ;

Number of terms of the set: 6;

Therefore, 21 is not a multiple of 6.

But for any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms.

For example:

Set of numbers: [1,2,3,4,5,] ;

Sum of the set:  1+2+3+4+5 = 15 ;

Number of terms of the set: 5;

Therefore, 15 is a multiple of 5.

And that's why we know that if y is always an even number (y = 2z), the sum of the consecutive integers (x) is not a multiple of y, therefore x/y cannot be an integer.

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Answer:

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Step-by-step explanation:

3t-7=5t

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-7=2t

t= -7/2

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Step-by-step explanation:

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Step-by-step explanation: it gave me the right answer after.

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Dmitry [639]

Answer:

  (ii) (x, y, z) = (110°, 30°, 30°)

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Step-by-step explanation:

The things you need to know and use are ...

  Opposite angles of a parallelogram are congruent.

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(ii) Angles B and D are opposite, so congruent:

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