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3 years ago

Ab and ba name the same ray. always sometimes never

Mathematics

2 answers:

vekshin13 years ago

7 0

The <em><u>correct answer</u></em> is:

never

Explanation:

A ray is named using the endpoint first and then another point on the ray. This means that ray AB has endpoint A and point B on the ray; ray BA has endpoint B and point A on the ray. These are not the same ray, as they do not have the same endpoint.

alina1380 [7]3 years ago

3 0

NEVA IS DA CORRECT ANSWER

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Can anyone help me on this problem? Please it doesn’t make sense to me...

Sav [38]

Answer:

Step-by-step explanation:

Cost per item is found by dividing the cost by the number of items. If the woman bought n items for $120, the cost of each item is $120/n. If the woman bought 24 more items, n+24, at the same price, then the cost per item is $120/(n+24). The problem statement tells us this last cost is $16 less than the first cost:

120/(n+24) = (120/n) -16

Multiplying by n(n+24) gives ...

120n = 120(n+24) -16(n)(n+24)

0 = 120·24 -16n^2 -16·24n . . . . . . subtract 120n and collect terms

n^2 +24n -180 = 0 . . . . . . . . . . . . . divide by -16 to make the numbers smaller

(n +30)(n -6) = 0 . . . . . . . . . . . . . . factor the quadratic

The solutions to this are the values of n that make the factors zero: n = -30, n = 6. The negative value of n has no meaning in this context, so n=6 is the solution to the equation.

The woman bought 6 items.

_____

Check

When the woman bought 6 items for $120, she paid $120/6 = $20 for each of them. If she bought 6+24 = 30 items for the same money, she would pay $120/30 = $4 for each item. That amount, $4, is $16 less than the $20 she paid for each item.

3 0

3 years ago

How much must you add to -12 to get greater than 5

pav-90 [236]

At least 15 b/c is you add QWERTY to -12, you get zero and adding 5 to get 15 in total.

7 0

3 years ago

Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?

Eva8 [605]

$\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6} }} \huge{) } \small{{}^{ {}^{ {}^{ {}^{ - 2} } } } }\\ \\ \\ \huge{(} \small{ \frac{4 \times m {}^{1} \times n {}^{1} }{ {m}^{ - 2} \times {n}^{6} }} \huge{)} \small{^{ {}^{ {}^{ {}^{ - 2} } } }} \\ \\ \\ \huge{(} \small{4 \times {m}^{1 - ( - 2)} \times {n}^{1 - 6}} \huge{)} \small{ {}^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \huge{(} \small{ 4 \times {m}^{1 + 2} \times {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \small{ {(4)}^{ - 2} \times ({m}^{3} ) ^{ - 2} \times {(n{}^{ - 5} )}^{ - 2} } \\ \\ \\ \frac{1}{ {4}^{2} } \times {m}^{ - 6} \times {n}^{ 10} \\ \\ \\ \frac{1}{16} \times \frac{1}{ {m}^{6} } \times {n}^{10} \\ \\ \\ \frac{ {n}^{10} }{16{m}^{6} }$

$\text{ Hence, option B is correct }$

7 0

3 years ago

Please help ASAP! All questions.

natka813 [3]

Answer:

I think i don't really know its been awhile for me.

Step-by-step explanation:

But i think you do 2 x 10 and what ever you get from that you multiply by 5 and what get from that you divide by 24.

I may not be right.

So please don't hate i tried.

4 0

3 years ago

The sum of two consecutive even integers is 118 what are the integers

Elanso [62]

Answer:

58 and 60

Step-by-step explanation:

well if we say that x is the first integer

then we have that the next one is

x+2

so we have

$x+(x+2)=118\\\\2x+2=118\\\\2x=116\\\\x=58$

and the other one is

$x+2=58+2=60$

3 0

2 years ago

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