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aleksandr82 [10.1K]
3 years ago
5

Which equation represents a quadratic function with a leading coefficient of 2 and a constant term of –3?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

D . f(x) =2x²+3x-3

Step-by-step explanation:

Given the equation as

f(x)=2x²+3x-3

The leading coefficient is in the term with the highest power , x², which is 2

The constant term is -3

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david quiere saber cuanto requiere invertir mensualmente para obtener $30,760.08 durante 6 meses si los invierte con el 12% capi
Akimi4 [234]

Answer:

A = $32,652.44

Step-by-step explanation:

Given: Principal (P) = 30,760.08, Annual Rate (R) = 12%, Time (t in years) = 0.5

To find: How much David needs to invest monthly

Formula: A = P(1 + r/n)^n^t

Solution: To find, simply add principal + interest

First, convert R as a percent to r as a decimal

r = R/100

r = 12/100

r = 0.12 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 30,760.08(1 + 0.12/12)(12)(0.5)

A = 30,760.08(1 + 0.01)(6)

A = $32,652.44

Therefore;  

The total amount David will obtain with 30,760.08 for 6 months, 12%is $32,652.44.

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3 years ago
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-5,424.3 ...............
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3 years ago
Teresa Gonzalez and Alan Carillo spent a total of $215.75 on their prom
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Iliana was part of a group that was working on changing 0.4 repeated to a fraction. Each member of the group had a different ans
amm1812
\bf 0.444444444\overline{4}\impliedby \textit{and keeps on going}\\\\
-------------------------------\\\\
\textit{let's say }\boxed{x=0.444444444\overline{4}}\quad \textit{ thus }10\cdot x=4.44444444\overline{4}
\\\\\\
\textit{wait a minute! }4.44444444\overline{4}\textit{ is really just }4+0.444444444\overline{4}

\bf \textit{but we know }x=0.444444444\overline{4} \textit{ so then }4+0.444444444\overline{4}=\boxed{4+x}
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\textit{wait a second! }10\cdot x\implies 10x=4.444444444\overline{4}=4+x
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thus\qquad 10x=4+x\implies 10x-x=4\implies 9x=4\implies \boxed{x=\cfrac{4}{9}}

you can check in your calculator.

anyhow, to get the "recurring decimal to fraction", you start by setting to some variable, "x" in this case, then move the repeating part to the left of the point by multiplying it by some power of 10, and then do the equating.
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Yes this is a correct statement.
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