Answer:Following is the c++ code for the problem:
#include <iostream>
using namespace std;
int main() {
int number;
cout<<"Enter the number"<<endl;
cin>>number;
int i=0,c=0,odd[500];
while(i<=number)//loop for printing the numbers form 0 to number.
{
cout<<i<<" ";
if(i%2!=0)// storing in the odd array if the number is odd.
{
odd[c++]=i;//storing odd numbers..
}
i++;
}
cout<<endl;
i=0;
cout<<"The odd numbers are "<<endl;
while(i<c)//loop to print the odd numbers.
{
cout<<odd[i]<<" ";
i++;
}
cout<<endl<<"The prime numbers are "<<endl;
i=0;
int sum=0;
while(i<c)//loop to print the prime numbers..
{
int div=2;
while(div<odd[i])
{
if(odd[i]%div==0)
break;
div++;
}
if(div==odd[i])
{
cout<<odd[i]<<" ";
sum+=odd[i];//updating the sum..
}
i++;
}
cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..
return 0;
}
Output :
Enter the number
49
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
The odd numbers are
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49
The prime numbers are
3 5 7 11 13 17 19 23 29 31 37 41 43 47
The sum of odd prime numbers is 326
.
Explanation:
First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.
It would be so you like chocolate because there is only two options. Yes or no
You can’t it’s impossible unless your a hackers
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Answer:
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