I need help with letter c and d
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Answer:
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.2622
The margin of error is:
M = T*s = 2.2622*0.3 = 0.68
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF
The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Since, Frank needs to save $600 to buy a set of golf clubs. He plans to save $75 per month.
Now, we have to determine the amount of money still he has to save (y) in relation to the number of months (x) in which he has saved money.
Let 'y' be the amount of money he still have to svae.
Let 'x' be the number of months he has saved money.
Total money saved yet = $75 x= $75x
He has to save $600 in total.
So, Money he still have to save = 600 - 75x
So, y=600-75x is the required equation.