Answer:
None of those answers are correct
Step-by-step explanation:
There are no real solutions
Let's solve your equation step-by-step.
2+2x−3
2x+3
=
3x+4
x+2
Step 1: Cross-multiply.
2+2x−3
2x+3
=
3x+4
x+2
(2+2x−3)*(x+2)=(3x+4)*(2x+3)
2x2+3x−2=6x2+17x+12
Step 2: Subtract 6x^2+17x+12 from both sides.
2x2+3x−2−(6x2+17x+12)=6x2+17x+12−(6x2+17x+12)
−4x2−14x−14=0
For this equation: a=-4, b=-14, c=-14
−4x2+−14x+−14=0
Step 3: Use quadratic formula with a=-4, b=-14, c=-14.
x=
−b±√b2−4ac
2a
x=
−(−14)±√(−14)2−4(−4)(−14)
2(−4)
x=
14±√−28
−8
Answer:
No real solutions.
